Java Iterator

Java Iterator

Hello Friends, How are you? Today I am going to solve the Java Iterator¬†Hackerrank Problem with a very easy explanation. In this article, you will get more than one approach to solving this problem. So let’s start- {tocify} $title={Table of Contents} Java Iterator class can help you to iterate through every element in a collection. Here is a simple example:

import java.util.*; public class Example{ public static void main(String []args){ ArrayList mylist = new ArrayList(); mylist.add(“Hello”); mylist.add(“Java”); mylist.add(“4”); Iterator it = mylist.iterator(); while(it.hasNext()){ Object element = it.next(); System.out.println((String)element); } } } {codeBox}

In this problem you need to complete a method func. The method takes an ArrayList as input. In that ArrayList there is one or more integer numbers, then there is a special string “###”, after that there are one or more other strings. A sample ArrayList may look like this:

element[0]=>42 element[1]=>10 element[2]=>”###” element[3]=>”Hello” element[4]=>”Java” {codeBox}

You have to modify the func method by editing at most 2 lines so that the code only prints the elements after the special string “###”. For the sample above the output will be:

Hello Java {codeBox}

Note: The stdin doesn’t contain the string “###”, it is added in the main method. To restore the original code in the editor, click the top left icon on the editor and create a new buffer.
Approach I: Java Iterator HackerRank Solution

// github.com/RodneyShag import java.util.*;
public class Main{ static Iterator func(ArrayList mylist){ Iterator it=mylist.iterator(); while(it.hasNext()){ Object element = it.next(); if (element.equals("###")) break; } return it; } @SuppressWarnings({ "unchecked" }) public static void main(String []args){ ArrayList mylist = new ArrayList(); Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int m = sc.nextInt(); for(int i = 0;i
No Comments

Sorry, the comment form is closed at this time.